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1st Year Physics Chapter 7 MCQs

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If your search is to get 1st Year Physics Chapter 7 MCQs with Answers Oscillations, then you’ve landed in the right place. The to and fro motion of a body about a mean position is oscillatory motion. This chapter is about oscillatory motions. So, the first topic is Simple Harmonic Motion. There are various terms explaining SHM. Next, we have Simple Harmonic Motion and Uniform Circular Motion which are described in a graph. Then there is the concept of Phase which is the angle that specifies the displacement as well as the direction of motion of the point executing SHM. The next is the Horizontal Mass Spring System. Simple Pendulum is the most important concept in this chapter followed by Energy Conservation in SHM. The next concept is Resonance which has some advantages and disadvantages. The chapter ends with the concept of Sharpness of Resonance. We have made a quiz for this chapter where you can solve the important MCQs of this chapter. Start the quiz and prepare for your entrance test.

1st Year Physics Chapter 7 MCQs with Answers Oscillations

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Physics Chapter 7

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When a body moving in a circle completes a quarter of its cycle then the time for this part of vibration is:

2 / 20

If the mass of the spring oscillator becomes half, its frequency will be

3 / 20

The distance covered by a body in one complete vibration is 20 cm. What is the amplitude of the body?

4 / 20

For a simple pendulum, the restoring force is caused by

5 / 20

Displacement of the body in S.H.M is equal to amplitude when the body is at

6 / 20

At Murree Hills (Assume the value of g changes). If we use a simple pendulum as a time standard, then a one-second duration will

7 / 20

Which one does not work according to resonance?

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The sharpness of resonance is:

9 / 20

For what displacement the P.E becomes 1/4 of its maximum value?

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If a hollow bob of a simple pendulum is filled with mercury that drains out slowly, its time period

11 / 20

The total energy of SHM is maximum at

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When the amplitude of a wave becomes double, its energy become

13 / 20

The SI unit of force constant is identical to that of:

14 / 20

The tension in the string of a simple pendulum is:

15 / 20

The force responsible for the vibratory motion of the simple pendulum is:

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If the length of a pendulum becomes four times, then its time period will become

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The time period of a second’s pendulum is:

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The total energy of a body executing S.H.M is directly proportional to:

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If a spring is halved then the spring constant of each half will be:

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In vibratory motion:

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